3y^2+20y=128

Solution for 3y^2+20y=128 equation:

Simplifying
3y2 + 20y = 128

Reorder the terms:
20y + 3y2 = 128

Solving
20y + 3y2 = 128

Solving for variable 'y'.

Reorder the terms:
-128 + 20y + 3y2 = 128 + -128

Combine like terms: 128 + -128 = 0
-128 + 20y + 3y2 = 0

Factor a trinomial.
(-32 + -3y)(4 + -1y) = 0

Subproblem 1
Set the factor '(-32 + -3y)' equal to zero and attempt to solve:

Simplifying
-32 + -3y = 0

Solving
-32 + -3y = 0

Move all terms containing y to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + -3y = 0 + 32

Combine like terms: -32 + 32 = 0
0 + -3y = 0 + 32
-3y = 0 + 32

Combine like terms: 0 + 32 = 32
-3y = 32

Divide each side by '-3'.
y = -10.66666667

Simplifying
y = -10.66666667
Subproblem 2
Set the factor '(4 + -1y)' equal to zero and attempt to solve:

Simplifying
4 + -1y = 0

Solving
4 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = 0 + -4
-1y = 0 + -4

Combine like terms: 0 + -4 = -4
-1y = -4

Divide each side by '-1'.
y = 4

Simplifying
y = 4
Solution
y = {-10.66666667, 4}